Ring of speed range of values

[Sky]

wow, thats even better than my kelek at DL20

[Pete Mack]

For a little thread necromancy:
I found a speed ring yesterday at +17 ... at DL 32.

[PowerWyrm]

http://angband.oook.cz/forum/showthread.php?t=8196&goto=nextnewest

[Ingwe Ingweron]

+23.

did you really have to resurrect a 7 year old thread?

I did a search for the relevant thread, rather than derail a current thread or create a new one. What's wrong with that? It seems the right approach to me.

[Sky]

+23.

did you really have to resurrect a 7 year old thread?

[Ingwe Ingweron]

Just found my fastest speed ring ever, by a wide margin, +21, in version 4.1.1

Unfortunately, @ already killed Morgoth, so it's not much use now.

[Storch]

Quite recently, bron mentioned =speed+23. Read the notes from http://angband.oook.cz/ladder-show.php?id=10647

I have found +23 RoS in V 3.0.6. It is quite odd that +23 is so common (relatively), isn't it?

[Nate]

Is the monster level that would be used to determine the item level the first value shown in the "W:" line in monster.txt? E.g, Morgoth=100 so item level for this calculation would be 100 unless I am on DL>100 in which case DL would be used? If so, does item level always revert to DL below DL 100 since DL will be > monster level?

[Nate]

And as it appears that the item level used in the m_bonus function is not necessarily simply the level on which the item is found, my calculation would only apply to ROS lying on the dungeon floor not in a vault. Yikes.

[Nate]

My new number includes the chances for all the possible values (1-10) of the d5m5 calculation, i.e. d5m5=10, consecutive coin flips=13; d5m5=9, consecutive coin flips=14, and so on down to d5m5=1, consecutive coin flips=22. The addition of these contributed more than I expected to the total chances.

[Nate]

Nope, I didn't do everything correctly. +23 is not nearly that rare. I was counting 64.5% as 1/64.5, not 64.5/100. The revised chances for ROS +23 at DL128 are approx. 1 in 26702.

The numbers for the Amulet of the Magi should be correct. Sorry! I'm actually surprised we haven't seen higher then +23 with all the players out there (+24 is about 1 in 53407).

[PowerDiver]

Only if the item is found on the floor outside of a vault. Items dropped by monsters use max(monster level, avg(monster level, dungeon level)), items dropped by chests use a hardcoded value depending on the type of chest, items in vaults get a boost applied to them depending on where they are in the vault, etc.

Nate is playing 312v2, which I believe uses max(monster level, dungeon level) before boosts.

[Nate]

If I'm doing everything correctly, chances of getting a ROS +23 at DL 128 IF the maximum of 10 is achieved from the d5m5 calculation are:

1/5(chances that rolling a 5 sided die results in a 5)*1/64.5(chances that the random number generated from the normal distribution with mean 5 std dev 1.25 is a 5)*1/8192(13 consecutive coin flips of the same result) = 1 in 2,641,920. To this must be added the chances of getting to +23 from each of the other possible results of the d5m5 check (1 through 9). This shouldn't add much to the total because the number of consecutive same coin flips required increases and those chances are small.

[Derakon]

Is the item level the level on which the item is found?

Only if the item is found on the floor outside of a vault. Items dropped by monsters use max(monster level, avg(monster level, dungeon level)), items dropped by chests use a hardcoded value depending on the type of chest, items in vaults get a boost applied to them depending on where they are in the vault, etc.

[Nate]

Is the item level the level on which the item is found?

If so, for a ROS at DL 128 the m5 enchantment should be a random # drawn from a normal distribution with mean = (5*128)/128 = 5 and std dev = 5/4 = 1.25

When I run this 1000 times in Excel using this function I found on the internet: =NORMINV(RAND(),5,1.25), I get 64.5% with a bonus of 5 or more.

For the Amulet of the Magi, I calculated means for the normal distribution of the following:

DL 50 = (3*50)/128 = 1.171875
DL 100 = (3*100)/128 = 2.34375
DL128 = (3*128)/128 = 3

Standard Deviation for each is 3/4 = .75

For 1000 random numbers these are the precentages I found for an Amulet of the Magi getting a +4 enchantment:

DL50 = 0%
DL100 = 7.1%
DL128 = 51.1%

0% doesn't mean it is impossible, just for that this run of 1000 numbers, none achieved the max enchantment at DL50.